simplify 2multiple 3-y (3x2y(x-z(x-2y
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2
Answer:
2x - 3y - 3x + 2y + x
Step-by-step explanation:
Explanation:
2x - 3y - [ 3x - 2y - [ x-z (x-2y) ]
= 2x - 3y - ( 3x - 2y - ( x - zx + 2yz) )
= 2x - 3y - ( 3x - 2y - x + zx - 2yz)
= 2x - 3y - 3x + 2y + x
Answered by
2
First we have to remove the parentheses
, then remove braces, and then the square brackets.
.Then we get, = 2x – 3y – [3x – 2y – {x – z – (x – 2y)})
= 2x – 3y – [3x – 2y – {x – z – x + 2y}]
= 2x – 3y – [3x – 2y – {- z + 2y}] = 2x – 3y – [3x – 2y + z – 2y]
= 2x – 3y – [3x – 4y + z]
On simplifying, we get = 2x – 3y – 3x + 4y – z
= – x + y – z
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