Question

Simplify:
(2p-3q)(2p+3q)+(3q+5r)(3q-5r)(5r+2p)(5r-2p)​

Answer 1

Answer:

The answer is 0.

Step-by-step explanation:

I think there is a plus sign between (3q-5r) and (5r+2p).

Hope this helps!!

Plz mark as the brainliest!!!!!

Answer 2

Answer:

$\red{ (2p-3q)(2p+3q)+(3q+5r)(3q-5r)+(5r+2p)(5r-2p)}$

$\green {= 0}$

Step-by-step explanation:

(2p-3q)(2p+3q)+(3q+5r)(3q-5r)+(5r+2p)(5r-2p)

= [ (2p)²-(3q)²]+ [(3q)²-(5r)²]+[(5r)² -(2p)²]

$\boxed { \pink { (a+b)(a-b) = a^{2} - b^{2} }}$

$= 4p^{2} - 9q^{2} + 9q^{2} - 25r^{2} +(25r^{2}-4p^{2}$

$= 0$

Therefore.,

$\red{ (2p-3q)(2p+3q)+(3q+5r)(3q-5r)+(5r+2p)(5r-2p)}$

$\green {= 0}$

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