Simplify (2p + q)(p - 2q + 3r) - (p - 3q)(-3p + q - 2r)
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Let us first take (2p+3q−4r)
2
(2p+3q−4r)
2
={2p+3q+(−4r)}
2
Using, (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ac
=(2p)
2
+(3q)
2
+(−4r)
2
+2(2p)(3q)+2(3q)(−4r)+2(−4r)(2p)
=4p
2
+9q
2
+16r
2
+12pq−24qr−16rp ...(i)
Now, let us solve,
(2p−3q−4r)
2
={2p+(−3q)+(−4r)}
2
Using, (a+b+c)
2
=a
2
+b
2
+c
2
+2ab+2bc+2ac
=(2p)
2
+(−3q)
2
+(−4r)
2
+2(2p)(−3q)+2(−3q)(−4r)+2(−4r)(2p)
=4p
2
+9q
2
+16r
2
−12pq+24qr−16rp .....(ii)
Adding the corresponding sides of (i)& (ii) we get,
(2p+3q−4r)
2
+(2p−3q−4r)
2
=4p
2
+9q
2
+16r
2
+12pq−24qr−16rp+4p
2
+9q
2
+16r
2
−12pq+24qr−16rp
=8p
2
+18q
2
+32r
2
−32rp.
=2(4p
2
+9q
2
+16r
2
−16rp).
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