Question

Simplify: 2root 12+root18-5root27-3roor32​

Answer 1

Answer:

$2 \sqrt{12} + \sqrt{18} - 5 \sqrt{27} - 3 \sqrt{32} =$

$2 \sqrt{4 \times 3} + \sqrt{9 \times 2} - 5 \sqrt{9 \times 3} - 3 \sqrt{16 \times 2}$

$4 \sqrt{3} + 3 \sqrt{2} - 15 \sqrt{3} - 12 \sqrt{2} = >$

$= > \sqrt{3} (4 - 15) + \sqrt{2} (3 - 12)$

$= > - 11 \sqrt{3} - 9 \sqrt{2}$

$= > - (11 \sqrt{3} + 9 \sqrt{2} ) \: \: ans...$

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Answer 2

Step-by-step explanation:

2√12 + √18 - 5√27 - 3√32

= 2√(2×2×3) + √(3×3×2) - 5√(3×3×3) - 3√(4×4×2)

= 4√3 + 3√2 - 15√3 - 12√2

= (4-15)√3 + (3-12)

= -11√3 - 9√2

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