Question

simplify:- (2x-3/x)(2x+3/x)​

Answer 1

Hope this solution might help u ...mark me brainliest...

Answer 2

Answer:

$4x^{2} - \frac{9}{x^{2}}$

Step-by-step explanation:

$(2x-\frac{3}{x})(2x+\frac{3}{x})\\\\2x(2x+\frac{3}{x}) - \frac{3}{x}(2x+\frac{3}{x})\\\\4x^{2} + 6 - 6 - \frac{9}{x^{2}}\\\\4x^{2} - \frac{9}{x^{2}}$

Also you can see for future reference that:

$(a+b)(a-b) = a^{2}-b^{2}\\\\a(a-b) + b(a-b)\\\\a^{2} - ab + ab - b^{2}\\\\a^{2}-b^{2}$

Using this identity

Here,

$a = 2x$ and

$b = \frac{3}{x}$ Thus

$(2x-\frac{3}{x})(2x+\frac{3}{x})\\\\=(2x)^{2} - (\frac{3}{x})^{2}\\\\=4x^{2} - \frac{9}{x^{2}}$

Thus the identity is true.............

Might help! Thanks