Question

simplify (2x-3y+4/z)^2 using suitable identity​

Answer 1

Answer:

(2x+3y+4z)

2

=(2x)

2

+(3y)

2

+(4z)

2

+(2×2x×3y)+(2×3y×4z)+(2×4z×2x)

(∵(a+b+c)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca)

=4x

2

+9y

2

+16z

2

+12xy+24yz+16zx

Hence, (2x+3y+4z)

2

=4x

2

+9y

2

+16z

2

+12xy+24yz+16zx.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

as we know that

(a +b +c) ^2 = a^2 +b^2 +c^2 +2ab +2bc +2ca

(2x -3y +4/z )^2

(2x)^2 +(3y)^2 +(4/z)^2 + 2*2x*-3y + 2*-3y*4/z + 2*2x*4/z

4x^2 +9y^2 +16z^2 -12xy -24y/z +16x/z