Math, asked by sachinyadav62527, 9 months ago

simplify (2x+3y)(z-w)+(2x-3y)(z+w)+5(xz+yw)​

Answers

Answered by sathi1234566
10

answer:-

9xz - yw

explaination:-

=> 2xz - 2xw + 3yz - 3yw + 2xz + 2xw - 3yz - 3yw + 5xz + 5yw

=> 9xz - 6yw + 5yw

=> 9xz - yw

hope this will help you

Answered by payalchatterje
0

Answer:

Required answer after simplication 9xz-yw.

Step-by-step explanation:

Given,

(2x + 3y)(z - w) + (2x - 3y)(z + w) + 5(xz + yw)

We are removing brackets,

2xz - 2xw + 3yz - 3yw + 2xz + 2xw - 3yz - 3yw + 5xz + 5yw

 = 9xz - 3yw + 2yw\\ = 9xz-yw

This is a problem of Algebra.

Some important Algebra formulas:

{(x + y)}^{2}  =  {x}^{2}  + 2xy +  {y}^{2} \\  {(x  -  y)}^{2}  =  {x}^{2}   -  2xy +  {y}^{2} \\  {(x  + y)}^{3}  =  {x}^{3}  + 3 {x}^{2} y + 3x {y}^{2}  +  {y}^{3}  \\   {(x   -  y)}^{3}  =  {x}^{3}   -  3 {x}^{2} y + 3x {y}^{2}   -  {y}^{3} \\  {x}^{3}  +  {y}^{3}  =  {(x  +  y)}^{3}  - 3xy(x + y) \\ {x}^{3}   -  {y}^{3}  =  {(x   -   y)}^{3}   +  3xy(x  -  y) \\  {x}^{2}  -  {y}^{2}  = (x + y)(x - y) \\    {x}^{2}  +  {y}^{2}  =  {(x - y)}^{2}   + 2xy \\ {x}^{2}   -  {y}^{2}  =  {(x   + y)}^{2}  - 2xy \\  {x}^{3}  -  {y}^{3}  = (x - y)( {x}^{2}  + xy +  {y}^{2} ) \\ {x}^{3}   +   {y}^{3}  = (x - + y)( {x}^{2}   -  xy +  {y}^{2} )

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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