Question

simplify ( 2x-4y +8z)^2​

Answer 1

Simplifying

2x + -4y + -8z = 0

Solving

2x + -4y + -8z = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4y' to each side of the equation.

2x + -4y + 4y + -8z = 0 + 4y

Combine like terms: -4y + 4y = 0

2x + 0 + -8z = 0 + 4y

2x + -8z = 0 + 4y

Remove the zero:

2x + -8z = 4y

Add '8z' to each side of the equation.

2x + -8z + 8z = 4y + 8z

Combine like terms: -8z + 8z = 0

2x + 0 = 4y + 8z

2x = 4y + 8z

Divide each side by '2'.

x = 2y + 4z

Simplifying

x = 2y + 4z

Answer 2

Answer:

4x^2+16y^2+64z^2-16xy-64yz+32xz

Step-by-step explanation:

We know that, (x+y+z)^2= x^2+y^2+z^2+2xy+2yz+2xz

Here we have,

x=2x, y=-4y, z=8z

Now put the values of x, y and z in the given formula.

=(2x)^2+(-4y)^2+(8z)^2+2(2x)(-4y)+2(-4y)(8z)+2(2x)(8z)

=4x^2+16y^2+64z^2-16xy-64yz+32xz

Hope it helps