simplify. (2x+5)square -(2x-5)square?
Answers
Answered by
327
(2x+5) ^2-(2x-5) ^2
by using identity
a^2-b^2=(a-b) (a+b)
here
a=(2x+5)
b=(2x-5)
so
(2x+5) ^2-(2x-5) ^2=[2x+5-(2x-5) ][2x+5+2x-5]
=10×4x
=40x
by using identity
a^2-b^2=(a-b) (a+b)
here
a=(2x+5)
b=(2x-5)
so
(2x+5) ^2-(2x-5) ^2=[2x+5-(2x-5) ][2x+5+2x-5]
=10×4x
=40x
Answered by
133
it is done by (a+b)²-(a-b)²=(a²+2ab+b²)-a²-2ab+b²;
so
(4x²+2×2x×5+25)-(4x²-2×2x×5+25)
4x²+20x+25-4x²+20x-25;
Ans=40x
40x=1;
Ans=x=1/40
hope u like it make it brainlist
so
(4x²+2×2x×5+25)-(4x²-2×2x×5+25)
4x²+20x+25-4x²+20x-25;
Ans=40x
40x=1;
Ans=x=1/40
hope u like it make it brainlist
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