simplify (2x+5)whole square -(2x-5) whole sqare
Answers
Answered by
16
1/4X^2+10+25
2/ -4X^2+10-25
Answered by
19
Answer:
simplify (2x+5)whole square -(2x-5) whole sqare = 40x
Step-by-step explanation:
(2x + 5)^2 - (2x - 5)^2
Expanding (2x + 5)^2 as (a+b)^2 = a^2 + b^2 + 2ab
and, expanding (2x - 5)^2 as (a-b)^2 = a^2 + b^2 - 2ab
∴ (2x + 5)^2 = 4x^2 + 25 + 20x ...(1) and,
(2x - 5)^2 = 4x^2 + 25 - 20x ...(2)
So, (2x + 5)^2 - (2x-+ 5)^2 is equal to (1) - (2)
∴ (2x + 5)^2 - (2x-+ 5)^2 = (4x^2 + 25 + 20x) - (4x^2 + 25 - 20x)
= 40x
∴ (2x + 5)^2 - (2x-+ 5)^2 is equal to 40x.
Similar questions