Math, asked by vikasgugnani4833, 1 year ago

simplify (2x+5)whole square -(2x-5) whole sqare

Answers

Answered by charafbkm
16

1/4X^2+10+25

2/ -4X^2+10-25


Answered by GulabLachman
19

Answer:

simplify (2x+5)whole square -(2x-5) whole sqare = 40x

Step-by-step explanation:

(2x + 5)^2 - (2x - 5)^2

Expanding (2x + 5)^2 as (a+b)^2 = a^2 + b^2 + 2ab

and, expanding (2x - 5)^2 as (a-b)^2 = a^2 + b^2 - 2ab

∴ (2x + 5)^2 = 4x^2 + 25 + 20x                     ...(1)    and,

(2x - 5)^2 = 4x^2 + 25 - 20x                          ...(2)

So, (2x + 5)^2 - (2x-+ 5)^2 is equal to (1) - (2)

∴ (2x + 5)^2 - (2x-+ 5)^2 = (4x^2 + 25 + 20x) - (4x^2 + 25 - 20x)

= 40x

∴  (2x + 5)^2 - (2x-+ 5)^2 is equal to 40x.

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