Question

Simplify (2x +5) (x-3) +15​

Answer 1

Step-by-step explanation:

(

2

+

5

)

(

−

3

)

+

1

5

(2x+5)(x-3)+15

(2x+5)(x−3)+15

Simplify

1

Distribute

(

2

+

5

)

(

−

3

)

+

1

5

{\color{#c92786}{(2x+5)(x-3)}}+15

(2x+5)(x−3)+15

2

(

−

3

)

+

5

(

−

3

)

+

1

5

{\color{#c92786}{2x(x-3)+5(x-3)}}+15

2x(x−3)+5(x−3)+15

2

Distribute

2

(

−

3

)

+

5

(

−

3

)

+

1

5

{\color{#c92786}{2x(x-3)}}+5(x-3)+15

2x(x−3)+5(x−3)+15

2

2

−

6

+

5

(

−

3

)

+

1

5

{\color{#c92786}{2x^{2}-6x}}+5(x-3)+15

2x2−6x+5(x−3)+15

3

Distribute

2

2

−

6

+

5

(

−

3

)

+

1

5

2x^{2}-6x+{\color{#c92786}{5(x-3)}}+15

2x2−6x+5(x−3)+15

2

2

−

6

+

5

−

1

5

+

1

5

2x^{2}-6x+{\color{#c92786}{5x-15}}+15

2x2−6x+5x−15+15

4

Combine like terms

2

2

−

6

+

5

−

1

5

+

1

5

2x^{2}{\color{#c92786}{-6x}}+{\color{#c92786}{5x}}-15+15

2x2−6x+5x−15+15

2

2

−

−

1

5

+

1

5

2x^{2}{\color{#c92786}{-x}}-15+15

2x2−x−15+15

5

Add the numbers

2

2

−

−

1

5

+

1

5

2x^{2}-x{\color{#c92786}{-15}}+{\color{#c92786}{15}}

2x2−x−15+15

2

2

−

2x^{2}-x

2x2−x

Solution

2

2

−

Answer 2

Solution :

$\implies (2x+5)(x-3)+15 = 0$

$\implies (2x^{2} -6x+5x-15)+15=0$

$\implies (2x^{2} -x-15)+15 = 0$

$\implies 2x^{2} - x - 15 + 15 =0$

$\implies 2x^{2} - x = 0$