simplify (2x-y+3z)(2x-y-3z) and thus find the value of the expression for x= -1, y= 2 , z=0 *
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answer is 16
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Answer:
2x(2x-y-3z)-y(2x-y-3z)+3z(2x-y-3z)
4x^2-2xy-6xz-2xy+y^2+3zy+6xz-3zy-9z^2
4x^2+y^2-9z^2-4xy-6xy+6xy-3zy+3zy
4x^2+y^2-9z^2-4xy-0-0
4x^2+y^2-9z^2-4xy --------------------- eq. 1
now putting values as x=-1,y=2,z=0 in equation 1
4(-1)^2+(2)^2-9(0)^2-4(-1)(2)
4(1)+4-0+8
4+4+8-0
16-0
16
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