simplify :-(√3+√11) ^2 + (√3 -√11) ^2
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(√3+√11) ^2 + (√3 -√11) ^2
= [(√3)^2 + (√11)^2 + 2(√3)(√11)] + [(√3)^2 + (√11)^2 - 2(√3)(√11)]
= [3 + 11 + 2(√3)(√11)] + [3 + 11 - 2(√3)(√11)]
= 14 + 2(√3)(√11) + 14 - 2(√3)(√11)
= 28 (Answer)
Hope it helps you...
= [(√3)^2 + (√11)^2 + 2(√3)(√11)] + [(√3)^2 + (√11)^2 - 2(√3)(√11)]
= [3 + 11 + 2(√3)(√11)] + [3 + 11 - 2(√3)(√11)]
= 14 + 2(√3)(√11) + 14 - 2(√3)(√11)
= 28 (Answer)
Hope it helps you...
Answered by
1
Step-by-step explanation:
(√3+√11)^2 + (√3-√11)^2
=[(√3)^2+(√11)^2 + 2(√3) (√11)]+ [√3)^2+(√11)^2-2(√3)(√11)]
[3+11+2(√3)(√11)] + [3+11-2(√3) (√11)]
14+2(√3)(√11)+14-2(√3)(√11)
28 (your answer)
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