Simplify √3-√2/√3+√2 + √3+√2/√3-√2
By rationalising the denominator
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The answer would be 0
Step-by-step explanation:
Conjugate of a first term (√2+√3) is
(√2-√3)
Conjugate of second term (√6+√3) is (√6-√3)
Conjugate of third term (√6+√2) is (√6-√2)
In denominator FORMULA used=
(a+b)(a-b)= a² - b²
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answer is 2 root 3 see the solution in photo
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