Math, asked by devchandh2, 1 year ago

simplify√3-√2/√3+√2+√3+√3/√3-√2


DaIncredible: hey
DaIncredible: is there any mistake
devchandh2: what
DaIncredible: i think √3 = √2
DaIncredible: in question
DaIncredible: see once
DaIncredible: am i right??
DaIncredible: plz see once

Answers

Answered by DaIncredible
1
Hey friend,
Here is the answer you were looking for:
 \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3 }  +  \sqrt{2} }  +  \frac{ \sqrt{3} +  \sqrt{3}  }{ \sqrt{3} -  \sqrt{2}  }  \\  \\ so \: the \: solution \: will \: be \\  \\ using \: identity \\ (a + b)(a - b) =  {a}^{2}   -  {b}^{2} \\   \\ =  \frac{ \sqrt{3} \times  \sqrt{ 3} +  \sqrt{3} \times  \sqrt{3}    -  \sqrt{2} \times  \sqrt{3}  - \sqrt{2} \times  \sqrt{3}   }{ {( \sqrt{3}) }^{2}  -  {( \sqrt{2} )}^{2} }  \\  \\  \\  =  \frac{3  + 3 -  \sqrt{6}  -  \sqrt{6}  }{3 - 2}  \\  \\  = 6 - 2 \sqrt{6}  \\  \\

Hope this helps!!!

@Mahak24

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