Question

Simplify:√3-√2÷√3+√2

Answer 1

$\bf \large \: please \: refer \: in \: atthment$

Answer 2

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The rationalising factor of√3+√2 is √3-√2.

Multiply the numerator and denominator by √3-√2.Then we get

$\frac{√3-√2}{√3+√2}$×$\frac{√3-√2}{√3-√2}$

$\implies$$\frac{(√3-√2)²}{(√3)²-(√2)²}$

$\implies$$\frac{(√3)²-2(√3)(√2)+(√2)²}{3-2}$

[Since,(a-b)²=a²-2ab+b²]

$\implies$$\frac{3-2√6+2}{1}$

[Since,(a+b)(a-b)=a²-b²]

$\implies$5-2√6