Simplify (√3+2) (√3-2)
Answers
Answered by
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hey mate!
(√3+2)(√3-2)
that is (a+b)(a-b)=a^2-b^2
so, (√3+2)(√3-2)=√3^2-2^2
=3-4=-1
(√3+2)(√3-2)
that is (a+b)(a-b)=a^2-b^2
so, (√3+2)(√3-2)=√3^2-2^2
=3-4=-1
shaik1276:
Thanks for the help mate
Answered by
2
Concept
The polynomial equations of degree two in one variable of form f(x) = ax2 + bx + c = 0 and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f. (x).
Given
The equation given is (√3+2) (√3-2)
Find
We need to Simplify (√3+2) (√3-2)
Solution
The given equation (√3+2) (√3-2) is in the form of general equation (a+b)(a-b)
Now we know that a^2-b^2 = (a+b)(a-b)
Applying the formula We get
(√3)^2-(2)^2 = 3-4
= -1
Hence the simplification is -1
#SPJ2
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