Question

Simplify 3√2/√6-√3. + 2√3/√6+2. -4√3/√6-√2

Answer 1

3√2 / √3 * (√2 - 1)    +    2√3 / √2 * (√3 + √2)      -     4√3 / √2 * ( √3 - 1)
= √6 / √2 -1    +     √6 / √3 + √2        -      2√6 / √3 - 1
= √6 ( √2 + 1) / √2² - 1²     +     √6 (√3 - √2) / √3² +√2²   -   2√6 (√3 + 1)/ √3² - 1²
= 2√3 + √6 / 2 -1     +    3√2 - 2√3 / 3 -2     -     6√2 - 2√6 / 3 - 1
2√3 + √6 / 1      +      3√2 - 2√3 / 1     -     2 * (3√2 + √6) / 2
= 2√3 - 2√3 + √6 - √6 + 3√2 - 3√2 = 0
please mark as brainliest ..............

Answer 2

ANSWER

3√2/√3*(√2-1)+2√3/√2* (√3+√3)4√3+√2*(√3-1)

=√6/√2-1+√6/(√3-1) 2 √6/√3-1

=√6(√2+1 )/√2²-1 ²+√6(√3-√2)/√3²+√2²-2 √6(√3+1)/√3²-1²

=2√3+√6/2-1+3√2-2√3/3-2 6√2-2√6/3-1

=2√3 + √6/1 + 3√2 - 2√3/1 - 2*(3√2+√(6)/2

=2√3-2√3+√6-√6+3√2 - 3√2

=0

PLEASE MARK BRAINLIST