Question

simplify: [3/216^2/3] +[2/256^-3/4] + [2/(243)^-1/5]

Answer 1

Hey friend,
Here is the answer you were looking for:
$(\frac{3}{ {216}^{ \frac{2}{3} } } ) + ( \frac{2}{ {256}^{ - \frac{3}{4} } } ) + ( \frac{2}{ {243}^{ - \frac{1}{5} } } ) \\ \\ = ( \frac{3}{ {6}^{3 \times \frac{2}{3} } } ) + ( \frac{2}{ {2}^{8 \times - \frac{3}{4} } } ) + ( \frac{2}{ {3}^{5 \times - \frac{1}{5} } } ) \\ \\ = ( \frac{3}{ {6}^{2} } ) + ( \frac{2}{ {2}^{2 \times - 3} } ) + ( \frac{2}{ {3}^{ - 1} } ) \\ \\ = \frac{2}{36} + \frac{2}{ {2}^{ - 6} } + \frac{2}{ {3}^{ - 1} } \\ \\ = \frac{2}{36} + 2 \times \frac{1}{64} + 2 \times \frac{1}{3} \\ \\ = \frac{2}{36} + \frac{1}{32} + \frac{2}{3} \\ \\ = \frac{2 \times 8 + 1 \times 9 + 2 \times 96}{288} \\ \\ = \frac{16 + 9 +192 }{288} \\ \\ = \frac{217}{288}$


Hope this helps!!!!

@Mahak24

Thanks....
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