Question

simplify (3√27/125) -² + (³√27/125) -4
Please answer my question ​
I will mark him or her as brainliest

Answer 1

☆I HOPE IT'S HELPFUL FOR YOU☆

Answer 2

Concept

A number's exponent indicates how many times it should be multiplied. The BODMAS rule is arranged according to the letters in the acronym BODMAS, which stand for brackets, order of powers or roots, division, and multiplication. A stands for addition and S for subtraction. According to the BODMAS rule, multi-operator mathematical equations must be resolved in the BODMAS order from left to right.

Given

$\sqrt[3]{\frac{27}{125} } ^{-2} +\sqrt[3]{\frac{27}{125} } ^{-4}$

To Find

We have to find the simplified form of the given exponential expression.

Solution

According to the problem,

$\sqrt[3]{\frac{27}{125} } ^{-2} +\sqrt[3]{\frac{27}{125} } ^{-4}$

$= \sqrt[3]{\frac{3^{3} }{5^{3} } } ^{-2} +\sqrt[3]{\frac{3^{3} }{5^{3} } } ^{-4}$

$=(\frac{3}{5}) ^{-2} +(\frac{3}{5}) ^{-4} =(\frac{5}{3}) ^{2} +(\frac{5}{3} )^{4}$

$=\frac{25}{9} +\frac{625}{81} =\frac{225+625}{81} =\frac{850}{81}$

Hence, simplified form of $\sqrt[3]{\frac{27}{125} } ^{-2} +\sqrt[3]{\frac{27}{125} } ^{-4}$ is $\frac{850}{81}$.

#SPJ2