Simplify 3 - [ 3 - {3-(3-3-a²-b²)}]
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Answer:
3-[3-1(3-(3-3-a2-b2))]
=3-[3-1(3-(-a2-b2))]
=3-[3-1(3+a2+b2)]
=3-[3-1(a2+b2+3)]
=3-[3-a2-b2-3]
=3-[-a2-b2]
=3+a2+b2
=a2+b2+3
Hope it helps.
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