Question

simplify 3^3 √40 4^3√320​

Answer 1

Step-by-step explanation:

It's quite simple!

Soln: In this, first take the L.C.M of 40, 320, we get

L.C.M of 40 = 8×5

L.C.M of 320 = 8×8×5

Now, substitute the products in the problem.

= 3(³√40)-4(³√320)-(³√5)

= 3[³√(8×5)]-4[³√(8×8×5)]-(³√5)

= 3(2.³√5)-4(2.2.³√5)-(³√5)

= 6.³√5–16.³√5-³√5

Now, take ³√5 as common, we get

= ³√5(6–16–1)

= ³√5(-11)

= -³√5

Therefore, ³√5 is the answer for your question.

Answer 2

Step-by-step explanation:

$3 \sqrt[3]{40} - 4 \sqrt[3]{320} \\ = 3 \sqrt[3]{8 \times 5 } - 4 \sqrt[3]{8 \times 8 \times 5} \\ = 3 \times 2 \sqrt[3]{5} - 4 \times 4 \sqrt[3]{5 } \\ = 6 \sqrt[3]{5 } - 16 \sqrt[3]{5} \\ = - 10 \sqrt[3]{5}$