Simplify 3√48-4√75+5√192
Answers
Answered by
7
Answer:17√3
Hope you understand
If there is a perfect square inside the root
it will come out
For example : √4=√2²=2, √28=√2²×7=2√7
Square root of 48 is 4 times √3
Square root of 75 is 5 times √3
Square root of 192 is 8 times √3
If the number inside the root is equal
we can add them
4×√3+5×√3+8×√3
4 plus 5 plus 8 is 17
CONCLUSION
17√3 is the answer
Answered by
4
SIMPLIFY:
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SOLUTION:
= 
= ![\sqrt[3]{39} \sqrt{80} \sqrt{192} \sqrt[3]{39} \sqrt{80} \sqrt{192}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B39%7D++%5Csqrt%7B80%7D++%5Csqrt%7B192%7D+)
= ![\sqrt[3]{39} \times 4 \sqrt{5} \sqrt{192} \sqrt[3]{39} \times 4 \sqrt{5} \sqrt{192}](https://tex.z-dn.net/?f=++%5Csqrt%5B3%5D%7B39%7D++%5Ctimes+4++%5Csqrt%7B5%7D++%5Csqrt%7B192%7D+)
= ![\sqrt[3]{39} \times 4 \sqrt{5} 8 \sqrt{3} \sqrt[3]{39} \times 4 \sqrt{5} 8 \sqrt{3}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B39%7D++%5Ctimes+4++%5Csqrt%7B5%7D+8+%5Csqrt%7B3%7D+)
= ![4 \times 8 \ \sqrt[3]{39} \sqrt{5 \times 3} 4 \times 8 \ \sqrt[3]{39} \sqrt{5 \times 3}](https://tex.z-dn.net/?f=4+%5Ctimes+8+%5C+%5Csqrt%5B3%5D%7B39%7D++%5Csqrt%7B5+%5Ctimes+3%7D+)
= ![4 \times 8 \sqrt[3]{39} \sqrt{15} 4 \times 8 \sqrt[3]{39} \sqrt{15}](https://tex.z-dn.net/?f=4+%5Ctimes+8+%5Csqrt%5B3%5D%7B39%7D++%5Csqrt%7B15%7D+)
= ![32 \sqrt[3]{39} \sqrt{15} 32 \sqrt[3]{39} \sqrt{15}](https://tex.z-dn.net/?f=32+%5Csqrt%5B3%5D%7B39%7D++%5Csqrt%7B15%7D+)
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ANSWER:
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