Simplify 3^a × 4^a-2 × 125^a+1 / 27^a-1 × 8^a+1 × 5^a-2
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... c = C, a = – D. Then if 35 (T, h) meets 5, 2/(hc”) > 1/C so that, by (7), tan 0 < 1, C* < 2m” tan #6. This gives a contradiction since 2 tan #6 - 2(V2 – 1) < 1 and C* > ...
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