Math, asked by Subhjotkaur, 1 year ago

Simplify 3 root2 - 2root3 ÷ root8 + root27

Answers

Answered by siddhartharao77
6
= \ \textgreater \   \frac{3 \sqrt{2} - 2 \sqrt{3}  }{2 \sqrt{2} + 3 \sqrt{3}  }

= \ \textgreater \   \frac{3 \sqrt{2} - 2 \sqrt{3}  }{2 \sqrt{2} + 3 \sqrt{3}  } *  \frac{2 \sqrt{2} - 3 \sqrt{3}  }{2 \sqrt{2} - 3 \sqrt{3}  }

= \ \textgreater \   \frac{(3 \sqrt{2} - 2 \sqrt{3})(2 \sqrt{2} - 3 \sqrt{3} )   }{(2 \sqrt{2} + 3 \sqrt{3})(2 \sqrt{2}-3 \sqrt{3})    }

 = \ \textgreater \   \frac{12 - 9 \sqrt{6} - 4 \sqrt{6} + 18 }{8 - 27}

= \ \textgreater \   \frac{13 \sqrt{6} + 30 }{-19}


Hope this helps!

siddhartharao77: :-)
Anonymous: (-:
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