Simplify: (3+route7) (2+route5).
Or
(5+route11) (5-route11).
Answers
Answered by
8
Hiii friend,
(3+✓7)(2+✓5)
=> 3(2+✓5)+✓7(2+✓5)
=> 6 + 3✓5 + 2✓7 + ✓35
(2) (5+✓11)(5-✓11)
we know that,
(A+B)(A-B) => (A)²-(B)².
=> (5)² - (✓11)²
=> 25-11
=> 14
(3+✓7)(2+✓5)
=> 3(2+✓5)+✓7(2+✓5)
=> 6 + 3✓5 + 2✓7 + ✓35
(2) (5+✓11)(5-✓11)
we know that,
(A+B)(A-B) => (A)²-(B)².
=> (5)² - (✓11)²
=> 25-11
=> 14
DaIncredible:
great ma'am✌
Answered by
7
Hey friend,
Here is the answer you were looking for:
This will be done by the method of cross multiplication
Using the identity :
Hope this helps!!
If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.
@Mahak24
Thanks...
☺☺
Here is the answer you were looking for:
This will be done by the method of cross multiplication
Using the identity :
Hope this helps!!
If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.
@Mahak24
Thanks...
☺☺
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