Question

Simplify 3(tan^2 Theta - sec^2 Theta)

Answer 1

$1 + \tan {}^{2} Θ = \sec {}^{2} Θ$

$\tan^2Θ - \sec^2Θ = - 1$

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$3( \tan {}^{2} Θ - \sec {}^{2} Θ)$

$\large{ = 3( - 1)}$

$\huge\purple{\boxed{\mathbb{\red{= - 3}}}}$

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Answer 2

Answer:

-3

Step-by-step explanation: