Question

Simplify
3 - tanA / 3cosecA - secA

Thank you in advance :)
​

Answer 1

Answer:

3tanA=4

or, tanA=4/3=p/b

Using Pythagorus theorem, h²=p²+b² we get,

h²=4²+3²

or, h²=16+9

or, h²=25

or, h=5 (neglecting the negative sign)

∴, secA=h/b=5/3 and cosecA=h/p=5/4

i) √secA-cosecA/√secA+cosecA

=√(5/3-5/4)/(5/3+5/4)

=√(5/12)/√(35/12)

=√(5/12×12/35)

=√1/7

ii) 1-sinA/1+cosA

=(1-4/5)/(1+3/5)

={(5-4)/5}/{(5+3)/5}

=(1/5)/(8/5)

=1/5×5/8

=1/8

Hope it helps you..