Question

Simplify: 3
$\sqrt[3]{3 + \sqrt[2]{27 } } + \frac{7}{ \sqrt{3} }$
Please can anyone answer it ?​

Answer 1

Step-by-step explanation:

SymbolCommand\frac{1}{2} or \frac12\frac{2}{x+2}\frac{1+\frac{1}{x}}{3x + 2}

Notice that with fractions with a 1-digit numerator and a 1-digit denominator, we can simply group the numerator and the denominator together as one number. However, for fractions with either a numerator or a denominator that requires more than one character (or if the numerator starts with a letter), you need to surround everything in curly brackets.

Use \cfrac for continued fractions.

ExpressionCommand\cfrac{2}{1+\cfrac{2}{1+\cfrac{2}{1+\cfrac{2}{1}}}}

Hope u like my Answer and Mark me as Brainliest...

Answer 2

Step-by-step explanation:

$\sqrt[3]{3 + \sqrt[2]{27 } } + \frac{7}{ \sqrt{3} }$

$\sqrt[3]{3 + ( {27})^{ \frac{1}{2} } } + \frac{7}{ \sqrt{3} }$

$( {3})^{ \frac{1}{3} } + {(27)}^{ \frac{1}{2} \times \frac{1}{3} } + \frac{7}{ \sqrt{3} }$

${3}^{ \frac{1}{3} } + ({27})^{ \frac{1}{6} } + \frac{7}{ \sqrt{3} }$

$\sqrt[3]{3} + {3}^{ \cancel2 \times \frac{1}{ \cancel6} } + \frac{7}{ \sqrt{3} }$

$\sqrt[3]{3} + {3}^{ \frac{1}{3} } + \frac{7}{ \sqrt{3} }$

$\sqrt[3]{3} + \sqrt[3]{3} + \frac{7}{ \sqrt{3} }$

$2 \sqrt[3]{3} + \frac{7}{ \sqrt{3} }$