Question

Simplify (3 x minus 4 y) whole cube minus (3 X + 4 y) whole cube

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$=(-8y)(27x^2+16y^2)$

Step-by-step explanation:

According to the question,

Simplify $(3x - 4y)^3 - (3x + 4y)^3$

As we know,

$a^3-b^3 = (a-b)[a^2+ab+b^2]$ ...(1)

and $a^2+b^2= (a+b)^2-2ab$...(2)

Here,

$a=3x-4y\\\\b=3x+4y$

put equation 2nd into equation 1st

$=(a-b)[(a+b)^2-ab]$

put the value of a and b in the above equation,

$= [3x-4y-(3x+4y)] [(3x-4y+3x+4y)^2-(3x-4y)(3x+4y)]\\\\\\= [-8y][(6x)^2-(9x^2-16y^2)]\\\\\\= [-8y][36x^2-9x^2+16y^2]\\\\=(-8y)(27x^2+16y^2)$

Hence, after simplifying the equation we get $=(-8y)(27x^2+16y^2)$.