Question

Simplify 3 (x² + y² xy) +7(x^2)-(2^2) the result when x=1,y=-2​

Answer 1

⭐ Question :-

Simplify 3 (x² + y² xy) +7(x^2)-(2^2) the result when x=1,y=-2

⭐ Given :-

• Value of x = 1

• Value of y = 2

⭐ To find :-

• 3( x² + y² + xy ) + 7( x²) - (2²)

⭐ Solution :-

⇒3( x² + y² + xy) + 7( x²) - (2²)

Substituting the value of x and y :

⇒3( 1² + 2² + 1×2) + 7(1²) - (2²)

We will apply the BODMAS rule where,

B - Bracket

O - Of

D - Division

M - Multiplication

A - Addition

S - Subtraction.

⇒3( 1 + 4 + 2) + 7(1) - (4)

⇒3( 7) + 7(1) - (4)

⇒21 + 7 - 4

⇒28 - 4

⇒24

Therefore, when we simplify 3 (x² + y² xy) +7(x^2)-(2^2) we get the answer as 24.

Joyful learning!!! ⛅