Question

simplify √32+√48
_________
√8+√12

plz solve the question

Answer 1

HEY MATE!

$\sqrt{32} = \sqrt{16 \times 2} = {4 \sqrt{2} } \\ \\ \sqrt{48} = \sqrt{16 \times 3} = 4 \sqrt{3} \\ \\ \sqrt{32 } + \sqrt{48} = 4 \sqrt{2} + 4 \sqrt{3} = 4( \sqrt{2} + \sqrt{3})$
$\sqrt{8} = \sqrt{4 \times 2 } = 2 \sqrt{2 } \\ \\ \sqrt{12} = \sqrt{4 \times 3} = 2 \sqrt{3 } \\ \\ \sqrt{8 } + \sqrt{12} = 2( \sqrt{2} + \sqrt{3} )$
HENCE THE ANSWER IS 2 IF WE DIVIDE

Answer 2

√32 + √48 /√8 + √12
√4*√8 + √4*√12/√8+√12 (√4*√8=√32,√4 * √12 = √48)
2√8 + 2√12/√8+√12 ( √4=2 )
2(√8+√12)/1(√8+√12) ( 2 taken common and 1 taken common)
ans = 2/1= 2 (√8+√12 cancelled out)