Question

Simplify: 3a (a + b + c)-[(a - b)(a + c)-(b - c)(a + b)] and then find the value at a = 0,b = 1 and c = - 1. ​

Answer 1

Given:

we have equation  3a (a + b + c)-[(a - b)(a + c)-(b - c)(a + b)]

To Find:

Simplify the given equation for a=0,b=1,c = -1?

Step-by-step explanation:

• We have equation of the form

              3a (a + b + c)-[(a - b)(a + c)-(b - c)(a + b)]

• For simplyfying any algebric equation we need to know firstly we solve square bracets then curley bracets.

• Also here we follow the rule of BODMAS.

• Firstly put the value in given equation a = 0,b= 1,c = -1

             = 3(0) (0 + 1 + (-1))-[(0 - 1)(0 + (-1))-(1 - (-1))(0 + 1)]

             = 0( (0 + 1 + (-1))-[(-1)(-1)-2(1)]

             = 0-[1-2]

             =-(-1)

             =1

Hence, simplified form is 1.