Question

Simplify: 3a2 (4a–5) + 11 and then find its value for a = –1.

Answer 1

Answer

=-43

Step-by-step explanation:

3a2 (4a-5)+11

3×(-1)×2 (4a-5)+11

-6(4×(-1)-5)+11

-6× (-9)+11

-54+11

=-43 ans.

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Answer 2

Following are the steps for getting the answer:

Given:

3a² (4a–5) + 11

To find:

Simplify: 3a²(4a–5) + 11 and then find its value for a = –1.

Solution:

we have to simplify the equation 3a²(4a–5) + 11

=3a²(4a–5) + 11

=(12a³-15a²) +11

Now, put a=-1 in the (12a³-15a²) +11

=(12a³-15a²) +11

=12×(-1)³-15(-1)²

the value of (-1)³=-1×-1×-1=-1

the value of (-1)²=-1×-1=1

=12×(-1)-15(1)

=-12-15

=-27

Thus, the simplification of 3a²(4a–5) + 11 is  (12a³-15a²) +11 and its value for  a = –1  is -27