Question

simplify (3x^-3y^3) ^-2 by exponent form​

Answer 1

Answer:

$\frac{x^6}{9y^6}$

Step-by-step explanation:

$\left(3x^{-3}y^3\right)^{-2}$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$$\Rightarrow =\frac{1}{\left(3x^{-3}y^3\right)^2}$

$=3^2\left(x^{-3}\right)^2\left(y^3\right)^2$

$=9\left(x^{-3}\right)^2\left(y^3\right)^2$

$=9x^{-3\cdot \:2}\times y^{3 \cdot2}$

$=9\cdot \frac{1}{x^6}y^6$

$=\frac{9y^6}{x^6}$

$=\frac{1}{\frac{9y^6}{x^6}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{1}{\frac{b}{c}}=\frac{c}{b} \Rightarrow =\frac{x^6}{9y^6}$

Answer 2

Answer:

it will help you

Step-by-step explanation:

(3x^-3y^3)^-2

= 3^2 (x-3)^-2 (y^3)-2

= 1/9 x^6 y^-6

=x^6/9y^6