Simplify 3x (4x – 5) + 3 and find its values for (i) x = 3 (ii) x =
1
2
.
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1
3x (4x − 5) + 3 = 12x2 − 15x + 3 (i) For x = 3, 12x2 − 15x + 3 = 12 (3)2 − 15(3) + 3 = 108 − 45 + 3 = 66 (ii) For
ii)x=1/2
3x(4x - 5) + 3
⇒ 3 × \bf \frac{1}{2}
2
1
(4 × \bf \frac{1}{2}
2
1
- 5) + 3 [pu the value of x = \bf \frac{1}{2}
2
1
⇒ \bf \frac{3}{2}
2
3
(2 - 5) + 3
⇒ \bf \frac{3}{2}
2
3
(-3) + 3
⇒ \bf \frac{-9}{2}
2
−9
+ 3
⇒ \bf \frac{-9 + 6}{2}
2
−9+6
⇒ \bf \frac{-3}{2}
2
−3
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3x(4x−5)+3=12x^2−15x+3
x=3 gives the value 12(9)−15×3+3
=108−45+3
=66
x=1/2 gives the value 12(1/4)−15×(1/2)+3
=3−7.5+3
= - 3/2
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