Math, asked by maliaka4681, 5 months ago

Simplify 3x (4x – 5) + 3 and find its values for (i) x = 3 (ii) x = 12

Answers

Answered by Auяoяà
29

Expression Given :

:\mapsto\rm{3x (4x - 5) + 3}

We have to simplify the Expression and then find the value of x .

  1. By putting the value of x as 3
  2. By putting the value of x as 12

Now let's Solve !

Simplifying :

:\leadsto\tt{3x (4x - 5) + 3}

:\leadsto\tt{3x\times4x - 3x \times5 + 3}

:\leadsto\tt{12x^2 - 15x + 3}

__________________

✴Step 1 :

Soluting by putting the value of x as 3

:\implies\rm{12x^2 - 15x + 3}

:\implies\rm{12(3)^2- 15(3) + 3}

:\implies\rm{12(3\times3) - 15 × 3 + 3}

:\implies\rm{12\times9 - 45+3}

:\implies\rm{108-45+3}

:\implies\rm{108+3-45}

:\implies\rm{111-45}

:\implies\rm{66}

✴Step 2 :

Soluting by putting the value of x as 12

:\implies\rm{12x^2 - 15x + 3}

:\implies\rm{12(12)^2 - 15(12) + 3}

:\implies\rm{12(12\times12) - 15 \times12 + 3}

:\implies\rm{12\times144- 180+3}

:\implies\rm{1728-180+3}

:\implies\rm{1728+3-180}

:\implies\rm{1731-180}

:\implies\rm{1551}

Thus ,

☆By putting the value of x as 3 the value of x we got is :

\blue{66}

☆And,By putting the value of x as 12 the value of x we got is :

\blue{1551}

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Answered by Anonymous
32

Question:

Simplify 3x (4x-5) + 3, and find its value for:

i) x = 3

ii) x = 12

____________________

Solution:

First we will simplify the given expression.

3x (4x-5) + 3

\implies \sf {12x^{2} - 15x + 3}

\implies \sf {12x^{2} - 15x + 3}

____________________

i) x = 3

Substitute the value of x as 3 in the simplified expression,

\implies \sf {12x^{2} - 15x + 3}

\implies \sf {12 \times 3^{2} - 15 \times 3 + 3}

\implies \sf {12 \times 9 - 45 + 3}

\implies \sf {108 - 45 + 3}

\implies \sf {63 + 3}

\boxed {\bf {\red {66}}}

____________________

ii) x = 12

Substitute the value of x as 12 in the simplified expression,

\implies \sf {12x^{2} - 15x + 3}

\implies \sf {12 \times 12^{2} - 15 \times 12 + 3}

\implies \sf {12 \times 144 - 180 + 3}

\implies \sf {1728 - 180 + 3}

\implies \sf {1548 + 3}

\boxed {\bf {\red {1551}}}

____________________

Final answer:

\bigstar {\sf {\green {When\ x = 3,\ then\ the\ value\ is\ 66.}}}

\bigstar {\sf {\gray {When\ x = 12,\ then\ the\ value\ is\ 1,551.}}}

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