Math, asked by harshit3818, 21 days ago

. Simplify 3y(2y-7) – 3(y-4) and evaluate them for y = -2 and y = 0

Answers

Answered by wwwyeswa2007
0

Answer:

put y=-2ans60 and y=0ans-12

Step-by-step explanation:

3y(2y-7)-3(y-4)

6y^2-21y-3y-12

6y^2-24y-12

put y=-2we get

6(-2)^2-24(-2)-12

6(4)-24(-2)-12

24+48-12

72-12

60

put y=0

6y^2-21y-12

6(0)^2-21(0)-12

-12

therefore y=-2 is 60

y=0 is -12

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