Question

Simplify 3y(4y-5) + 3 and find its value
for y = 3​

Answer 1

Value of expression $\bf \pink{ 3y(4y-5)+3\bigg|_{y=3}= 66}$.

Given:

• $3y(4y-5)+3$

To find:

• Simplify the given expression and find its value for y=3.

Solution:

Step 1:

Multiply 3y inside the bracket.

$3y(4y-5)+3= 3y(4y)-5(3y)+3$

or

$\bf 3y(4y-5)+3= 12y^2-15y+3$

Step 2:

Put the value of y.

Put y= 3

$= 12(3)^2-15(3)+3$

or

$= 12(9)-45+3$

or

$= 108-45+3$

or

$= 108-45+3$

or

$\bf 3y(4y-5)+3\bigg|_{y=3}= 66$

Thus,

Value of given expression at y= 3 is 66.

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Learn more:

1) Find the following products and then evaluate when x = 2, y=-1

(7x+9y^2)(3xy^2)

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2) Simplify 7x²(3x - 9) + 3 and find its values for x = 4 and x = 6

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Answer 2

Answer:

3y(4y-5)+3 in simplified form is: $12y^{2}-15y+3$

And the value of the equation 3y(4y-5)+3 for y= 3 is 66

Step-by-step explanation:

Given

3y(4y-5)+3

To simplify, we have to multiply the terms inside the bracket with 3y

That is,

3y(4y-5)+3

= (3y*4y)-(3y*5)+3

$=12y^{2}-15y+3$

So the simplified form is:

$12y^{2}-15y+3$

Now we have to substitute y= 3

That is,

$12y^{2}-15y+3= 12(3^{2})-(15*3)+3$

=(12*9)-45+3

=108-42

=66

So, the value of the equation 3y(4y-5)+3 for y= 3 is 66