Question

Simplify
(4^-1+8^-1)*(3/2)^-1.​

Answer 1

Answer:

$( {4}^{ - 1} + {8}^{ - 1}) \div (\frac{2}{3} )^{2} \\ \\ \frac{1}{4} + \frac{1}{8} \div \frac{3}{2} \\ = \frac{3}{8} \times \frac{2}{3} = \frac{1}{4}$

Step-by-step explanation:

hope it helps (~‾▿‾)~