simplify-
4√16-6 3√343+18×5√243-√196
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At STP,
P = 105 Pa
T= 273K
R = 8.31 J/K
Now, 1ml = 10-6 m3
From ideal gas equation,
Given,
Mass of 0.005 moles of gas X = 0.22 g
Therefore,
Mass of 1mole of gas X = 0.22 / 0.005
= 44g
Hence, the relative molecular mass of Gas X = 44g
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