Question

simplify(4√3-2√2)(3√2+4√3)​

Answer 1

Concept

The following are the basic rules and steps of simplifying any algebraic expression: Multiplying factors will remove any grouping symbols such as brackets and parenthesis. If the terms contain exponents, use the exponent rule to eliminate grouping. By adding or subtracting like terms, you can create a new term.

Given

$(4\sqrt{3} -2\sqrt{2})(3\sqrt{2} +4\sqrt{3} )$

Find

We are asked to simplify the given product

Solution

By considering the given product

$(4\sqrt{3} -2\sqrt{2})(3\sqrt{2} +4\sqrt{3} ) \\4\sqrt{3})(3\sqrt{2} +4\sqrt{3} )-2\sqrt{2}(3\sqrt{2} +4\sqrt{3} )\\12\sqrt{6} +48-12-8\sqrt{6} \\36+4\sqrt{6}$

Hence the simplification form is $36+4\sqrt{6}$

Answer 2

Concept:

The Bodmas rule is arranged according to the letters in the acronym BODMAS, which stand for brackets, order of powers or roots, division, and multiplication. A stands for addition and S for subtraction. According to the BODMAS rule, multi-operator mathematical equations must be resolved in the BODMAS order from left to right. Similar to how Addition and Subtraction depend on which comes first in the sentence, Division and Multiplication are thought of as interchangeable operations.

Given Information:

The expression to solve is given:

$(4\sqrt{3}-2\sqrt{2} )(3\sqrt{2}+4\sqrt{3} )$

To find:

Find the value of the given expression:

$(4\sqrt{3}-2\sqrt{2} )(3\sqrt{2}+4\sqrt{3} )$

Solution:

The expression is :

$(4\sqrt{3}-2\sqrt{2} )(3\sqrt{2}+4\sqrt{3} )$

Multiply the expressions in the bracket.

$12\sqrt{6}+ 16*3 -6*2-8\sqrt{6}$

=$36+4\sqrt{6}$

Hence, the answer is $36+4\sqrt{6}$.

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