Math, asked by sunibijupalazhi, 3 months ago

Simplify '4*(cos 42^(@) cos 102^(@) cos 114^(@) cos 174^(@))^(2)' into a rational number.​

Answers

Answered by RvChaudharY50
0

Simplify :- 4(cos 42° * cos 102° * cos 114° * cos 174°)² into a rational number .

Answer :-

→ 4(cos 42° * cos 102° * cos 114° * cos 174°)²

using,

  • cos (90° - θ) = sin θ
  • cos (90° + θ) = - sin θ

→ 4[sin 48° * (- sin 12°) * (- sin 24°) * ( - sin 84°)]²

→ 4[(-1) * sin 12° * sin 24° * sin 48° * sin 84° ]² --------- Eqn.(1)

solving in parts,

→ sin 12° * sin 48°

multiply and divide by sin 72°

→ (1/sin 72°)[ sin 12° * sin 48° * sin 72°]

using,

  • sin A * sin (60 - A) * sin (60 + A) = (1/4) sin 3A,

→ (1/sin 72°)(1/4)sin 36° ------ Eqn.(2)

similarly,

→ sin 24° * sin 84°

multiply and divide by sin 36°

→ (1/sin 36°)[ sin 24° * sin 36° * sin 84°]

→ (1/sin 36°)(1/4)sin 72°------- Eqn.(3)

multiply Eqn.(2) and Eqn.(3) ,

→ {(1/sin 72°)(1/4)sin 36°} * (1/sin 36°)(1/4)sin 72°

→ (1/4) * (1/4) * (sin 36°/sin 36°) * (sin 72°/sin 72°)

(1/16)

putting this value in Eqn.(1)

→ 4[(-1) (1/16)]²

→ 4 * (1/256)

(1/64) (Ans.)

Hence, our required rational number is (1/64) .

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