Math, asked by jagruthi60, 4 months ago

Simplify 4 to the power of-3 × y to the power of-5 divided by 2 to the power of-5 × 3 to the power of-6 × 9 to the power of-4​

Answers

Answered by premyadavk15gmailcom
0

Answer:

Sorry I didn't get a chance to me and I will be in the work

Answered by ramyadukuntla
0

Step-by-step explanation:

Simplify the following expression:

\mathbf{\color{green}{\dfrac{6^8}{6^5}}}

6

5

6

8

The exponent rules tell me to subtract the exponents. But let's suppose that I've forgotten the rules again. The " 68 " means I have eight copies of 6 on top; the " 65 " means I have five copies of 6 underneath.

\dfrac{6 \cdot 6 \cdot 6 \cdot 6 \cdot 6 \cdot 6}{6 \cdot 6 \cdot 6 \cdot 6 \cdot 6}

6⋅6⋅6⋅6⋅6

6⋅6⋅6⋅6⋅6⋅6

How many extra 6's do I have, and where are they? I have three extra 6's, and they're on top. Then:

= \dfrac{6 \cdot 6 \cdot 6}{1} = \mathbf{\color{purple}{6^3}}=

1

6⋅6⋅6

=6

3

Unless the instructions also tell you to "evaluate", you're probably expected to leave numerical exponent problems like this in exponent form. If you're not sure, though, feel free to add "= 216", just to be on the safe side.

Simplify the following expression:

\mathbf{\color{green}{\dfrac{\mathit{t}^{10}}{\mathit{t}^8}}}

t

8

t

10

How many extra copies of t do I have, and where are they? I have two extra copies, on top:

\dfrac{t^{10}}{t^8} = \dfrac{t \cdot t \cdot t \cdot t \cdot t \cdot t \cdot t \cdot t \cdot t \cdot t}{t \cdot t \cdot t \cdot t \cdot t \cdot t \cdot t \cdot t}

t

8

t

10

=

t⋅t⋅t⋅t⋅t⋅t⋅t⋅t

t⋅t⋅t⋅t⋅t⋅t⋅t⋅t⋅t⋅t

= \dfrac{t \cdot t}{1} = \mathbf{\color{purple}{\mathit{t}^2}}=

1

t⋅t

=t

2

Once you become comfortable with the "how many extras do I have, and where are they?" reasoning, you'll find yourself not needing to write things out and cancel off the duplicate factors. The answers will start feeling fairly obvious to you.

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