Simplify 4 y (3 y2−5 y+7) and find its value at y=0 .
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Answer:
Solve 3y(2y−7)−3(y−4)−63 for y=−2
First simplify it,
=6y
2
−21y−3y+12−63
=6y
2
−24y−51
Put y=−2
=6(−2)
2
−24(−2)−51
=6×4+48−51
6×4+48−51
24+48−51
=21
Step-by-step explanation:
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