Question

.Simplify 40+[20-{28÷7-3+(30-5 of 4)}]

Answer 1

Answer:  40+[20-{28÷7-3+(30-5 of 4)}] -49

Step-by-step explanation:  

40+[20-{28/7-3(30-5*4)}]

40+[20-{28/7-3(30-20)}]

40+[20-{28/7-3+10}]

40+[20-{4-3+10}]

40+[20-{14-3}]

40+[20-11}

40+9

49

hope its helpful : )

Answer 2

The given question is we have to simplify the given expression

The given expression is

.Simplify 40+[20-{28÷7-3+(30-5 of 4)}]

we have to simplify this by using the rule of BODMAS

Brackets orders division multiplication addition and subtraction

The given expression must be simplified as bracket by bracket.

$40 + (20 - ( \frac{28}{7} - 3 + (30 - 5 \times 4)))$

we have to solve the inner bracket 30-5*4

$30 - 5 \times 4$

By the rule multiplication must be done first, so we have

$30 - 20$

$40 + (20 - (\frac{28}{7} - 3 + (30 - 20))) \\ 40 + (20 - ( \frac{28}{7} - 3+ (10)))$

the next bracket should be solve

$40 + (20 - (4 - 3 + 10)) \\ = 40 + (20 - (1 + 10) \\ = 40 + (20 - 11) \\ = 40 + (9) \\ = 49$

The final answer is 49.

Therefore, the given expression is simplified.

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