Question

Simplify √40/√3. Please help me

Answer 1

Answer:

Step-by-step explanation:

hope this helps...

$\sqrt{40}/\sqrt{3} \\\sqrt{40} *\sqrt{3} /\sqrt{3}*\sqrt{3} \\\sqrt{120} /\sqrt{3} ^{2} \\\\\sqrt{120}/3\\ 2\sqrt{30} /3$

Answer 2

ANSWER:

${ \sf{\dfrac{ \sqrt{40} }{ \sqrt{3} } }}$

Simplify

${ \sf{ \frac{2 \sqrt{10} }{ \sqrt{3} } }}$

Rationalize the denominator

To rationalize we have multiply and divide with √3

${\bf{ \implies \frac{ 2\sqrt{10} ( \sqrt{3}) }{ \sqrt{3}( \sqrt{3} ) }}} \\ { \bf{ \implies \frac{2 \sqrt{30} }{3} }}$

We know that

√30 = √15 × 3 = √3² × 3 = 3√3

Hence, √30 = 3√3

${ \bf{ \implies \dfrac{2( \cancel3 \sqrt{3}) }{ \cancel3} }} \\ \implies{ \bf{2 \sqrt{3} }}$

Hence,

${ \tt{ \dfrac{ \sqrt{40} }{ \sqrt{3} } \to2 \sqrt{3} }}$

MORE INFORMATION:

$\star \: \: \sqrt[m]{ \sqrt[n]{a} } = \sqrt[mn]{a} \\ \star \dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}= \sqrt[n]{\dfrac{a}{b}}$