Question

Simplify : √48 -3×√108 +2√27 + √192​

Answer 1

This is the answers for this sum

Answer 2

Answer:

After simplification 0 is the value of $\sqrt{48} - 3\sqrt{108} + 2\sqrt{27} + \sqrt{192}$.

Step-by-step explanation:

Explanation:

$\sqrt{48} - 3$ × $\sqrt{108}$ + $2\sqrt{27}$ +$\sqrt{192}$

⇒$\sqrt{2.2.2.2.3}$ - 3 × $\sqrt{2.2.3.3.3}$ + 2$\sqrt{3.3.3}$ + $\sqrt{2.2.2.2.2.2.3}$

⇒4$\sqrt{3}$ - 3 ×2 ×3 $\sqrt{3}$ + 2× 3$\sqrt{3}$ + 8$\sqrt{3}$

Here we can see that roots are same.

⇒4 $\sqrt{3}- 18\sqrt{3} + 6\sqrt{3} + 8\sqrt{3}$

According to the BODMAS rule, first we solve addition part than subtraction.

⇒$(4\sqrt{3} +8\sqrt{3} +6\sqrt{3} )$ - $18\sqrt{3}$

⇒$18\sqrt{3}$ - $18 \sqrt{3}$

⇒ 0.

Final answer:

Hence, 0 is the required value of   $\sqrt{48} - 3\sqrt{108} + 2\sqrt{27} + \sqrt{192}$

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