Question

simplify (4a^2-6ab+9b^2) (2a+3b) and verify a=2, b=1​

Answer 1

Step-by-step explanation:

$(4 \times {2}^{2} - 6 \times 2 \times 1 + 9 \times {1}^{2} )(2 \times 2 + 3 \times 1) \\( 16 - 12 + 9)(4 + 3) \\ (4 + 9)(7) \\ 13 \times 7 \\ 91$

Answer 2

Answer:

a³+b³ = (a+b) (a² – ab + b²) using this

(4a^2-6ab+9b^2) (2a+3b)=(2a)³+(3b)³

8a³+27b³. (put a=2 and b=1)

8(2)+27(1)

16+27

43