Math, asked by ravindrajacharya94, 10 months ago

simplify (4a-3)³-(4a+3)³ ​

Answers

Answered by rudraaggarwal239982
24

Answer:

here is your answer mate...

Step-by-step explanation:

(4a-3)^3=(4a)^3-3(4a)^2b+3(4a)(3)^2-(3)^3

= 64a^3 - 48a^2b + 108a-27

(4a+3)^3=(4a)^3+3(4a)^2b+3(4a)(3)^2+(3)^3

= 64a^3 + 48a^2b + 108a+27

(4a-3)^3 + (4a+3)^3 = 128 a^3 + 216 a

plz plz plz mark me as brainliest plzz...

Answered by pc0354525
17

Answer:

Step-by-step explanation:

Formula:

a^3-b^3 = (a-b) (a^2+b^2+ab)

Solution:

let (4a-3) be a

    and

    (4a+3) be b

then

a^3-b^3 = (a-b) (a^2+b^2+ab)

(4a-3)^3 - (4a+3)^3

step 1 = [(4a-3) - (4a+3) [(4a-3)^2 + (4a+3)^2+(4a-3) (4a+3)]

step 2 = [4a-3-4a-3] [(16a^2+9) + (16a^2+9) + (16a^2+12a-12a-9)]

step 3 = [-6] [16a^2+9+16a^2+9+16a^2+12a-12a-9]

step 4 = [-6] [48a^2+9]

step 5 = (-288a^2-54)

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